怎么把有2列纳秒时间戳的文本导入DolphinDB database分布式表

文本文件样本数据如下所示,其中SendingTimeInNano和origSendingTimeInNano是纳秒时间戳：

SendingTimeInNano#securityID#origSendingTimeInNano#bidSize
1579510735948574000#27522#1575277200049000000#1
1579510735948606000#27522#1575277200049000000#2
1579510735948649000#27702#1575277200049000000#3
1579510735948676000#27702#1575277200049000000#4
1579510735948711000#30495#1575277200049000000#5
1579510735948762000#29088#1575277200049000000#6
...

dolphindb database分布式表建表脚本如下，SendingTimeInNano和securityID是2个分区字段：

x=20*seq(500,2500);

dbSendingTimeInNano = database(, VALUE,  2020.01.11..2020.01.22);

dbSecurityIDRange = database(, RANGE, x);

db = database("dfs://dolphinDBHYTEST3", COMPO, [dbSendingTimeInNano, dbSecurityIDRange]);

nameCol = `SendingTimeInNano`securityID`origSendingTimeInNano`bidSize;

typeCol = [`NANOTIMESTAMP,`INT,`NANOTIMESTAMP,`INT];

schemaTb = table(1:0,nameCol,typeCol);

db = database("dfs://dolphinDBHYTEST3");

nx = db.createPartitionedTable(schemaTb, `nx, `SendingTimeInNano`securityID);

请教怎样才能高效地把文本数据导入上述dolphindb分布式表？

0 条评论

默认排序时间排序

1 个回答

logger 2021-06-15 14:46

可试试下面代码：

def dataTransform(mutablet){

return t.replaceColumn!(`SendingTimeInNano, nanotimestamp(t.SendingTimeInNano)).replaceColumn!(`origSendingTimeInNano, nanotimestamp(t.origSendingTimeInNano))

}

pt=loadTextEx(dbHandle=db,tableName=`nx , partitionColumns=`SendingTimeInNano`securityID,filename="nx.txt",delimiter='#',transform=dataTransform);

更进一步的说明请参阅https://github.com/dolphindb/...

怎么把有2列纳秒时间戳的文本导入DolphinDB database分布式表

1 个回答

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