Usage: ploop(func, args...). The length of all args must be consistent.

def piep(c,mutable data_dhz){
 Future_s=select last(askPrice1) as askPrice1,last(bidPrice1) as bidPrice1 from Future_source where product=`j
 Trading_t=select * from Trading_Table
 configs=select * from trad_model_config where strategy=`DHZ,hide>0,state>0
 Func_DHZ(c,configs,data_dhz,Trading_t,Future_s)
 }
 
def DHZ(mutable ss,msg){
 data_dhz=select last(product) as symbol,last(time) as time,first(price_index) as open,max(price_index) as high,min(price_index) as low,last(price_index) as close,last(price_index) as askPrice1,last(price_index) as bidPrice1 from future_index where product =`j group by tradingDay,time.minute()  
 configs=select * from trad_model_config where strategy=`DHZ,hide>0,state>0
 
 conf=[]
 for (c in 0..(size(configs)-1)){
  conf.append!(c)
  }
 ploop(piep,conf,data_dhz)

}

上述代码，在执行时报错：msgId=32223644 length=400 exception=Usage: ploop(func, args...). The length of all args must be consistent.
这里有方法改成参数数量不一致也能运行吗？
我的需求是固定data_dhz，而conf是多个,即输入ploop(piep,[1,2,3,4],data_dhz)，达到ploop(piep,[1，2,3,4],[data_dhz，data_dhz，data_dhz，data_dhz])的效果。谢谢！