lpad函数在str的左边填充指定字符串
t.replaceColumn!(`time, temporalParse(lpad(string(t.time),9,`0), "HHmmssSSS"))
样例数据如下,请问如何对8点、9点的原始数据的左边进行补0,希望转成08:45:06.000,10:30:02.000
t = table(`84506000`93001000`103002000 as time, 1..3 as price)
lpad函数在str的左边填充指定字符串
t.replaceColumn!(`time, temporalParse(lpad(string(t.time),9,`0), "HHmmssSSS"))