教这个怎么做高效?将tb中等于字典d1 key的数据全部修改为对应的d1的值
d1 = {'a1':'a','a2':'a','b1':'b'}d1tb = table(`a1`a2`a3 as `a,`b1`b2`b3 as `b)tb
d1 = {"a1":"a","a2":"a"}tb = table(`a1`a2`a3 as `a,`b1`b2`b3 as `b)update tb set a=nullFill!(string(d1[a]), a)
