fromJson不能接受向量作为参数,可以用each函数来实现:
x1='{"name":"","form":"scalar","type":"double","value":"2.1E+5"}' x2='{"name":"","form":"scalar","type":"double","value":"100"}' t=table(1..2 as id,[x1,x2] as val) select id,each(fromJson,val) from t
在DolphinDB database中有下面代码:
x1='{"name":"","form":"scalar","type":"double","value":"2.1E+5"}' x2='{"name":"","form":"scalar","type":"double","value":"100"}' t=table(1..2 as id,[x1,x2] as val) typestr(fromJson(x1)) //DOUBLE select id,fromJson(val) from t
执行最后一行语句时,提示
The data form is not supported
请问可以用什么方法解决?